COMO RESOLVER 2^x = 5^1
2^x = 5^1 5=10/2
2^x = (10/2)^1
2^x = 10/2 ... tomando o log em ambos lados
log 2^x =log(10/2)
xlog 2 = log10- log2 ....... log10= 1 log 2= 0,3010
x= (log10-log2)/log2
x= (1-log2)/log2
ou
x= ( 1-0,3010)/0,3010
x= 0,699/0,3010
x= 2,3222
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2^x = 5
x*log(2) = log(5)
x = log(5)/log(2) = (1 - log(2))/log(2) = 2,3219
pronto
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Verified answer
2^x = 5^1 5=10/2
2^x = (10/2)^1
2^x = 10/2 ... tomando o log em ambos lados
log 2^x =log(10/2)
xlog 2 = log10- log2 ....... log10= 1 log 2= 0,3010
x= (log10-log2)/log2
x= (1-log2)/log2
ou
x= ( 1-0,3010)/0,3010
x= 0,699/0,3010
x= 2,3222
///////////////////////////////
2^x = 5
x*log(2) = log(5)
x = log(5)/log(2) = (1 - log(2))/log(2) = 2,3219
pronto