You have to equate coefficients. Since there is an equality between the left and right hand side, if you have a complex number "a+bi," then the "a" and "b" must be equal on each side such that the numbers are the same.
(2x-1) + i = y - (3-y)i
So you have that 2x-1 = y to equate the "a" coefficients
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You have to equate coefficients. Since there is an equality between the left and right hand side, if you have a complex number "a+bi," then the "a" and "b" must be equal on each side such that the numbers are the same.
(2x-1) + i = y - (3-y)i
So you have that 2x-1 = y to equate the "a" coefficients
And 1 = -(3-y) to equate the "b" coefficients
1 = -3 + y
y = 4
2x -1 = y
2x - 1 = 4
2x = 5
x = 5/2
Well, if x and y can be anything, then there's no way to solve this.
However, if we just want real values for x and y, then here's how it works:
For a complex number to be equal to another complex number, we need two things:
(1) Real parts are equal.
2x - 1 = y
(2) Imaginary parts are equal.
1 = -(3 - y) = -3 + y
Now we can solve.
1 = -3 + y
y = 4
Substituting this into the equation 2x - 1 = y, we get
2x - 1 = 4
2x = 5
x = 5/2.
So the answer is:
x = 5/2, y = 4.
1 = y-3
2x-1 = y
1-2x = -2
x = 2/3
y = 1/3
wow, i did do maths a lONg time ago, I just remember after seeing these guys answeres.lol.
I use to do these things, so weird, i kind of miss it. lol