Find the value of k which makes the function f(x)=k√(x) a probability density function on the interval [0,4]
k=?
Integral (4 to 0) (k√(x)) dx = 1
2/3 k x^(3/2) | (4 to 0) = 1
2/3 k (8 - 0) = 1
16/3 k = 1
k = 3/16
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Verified answer
Integral (4 to 0) (k√(x)) dx = 1
2/3 k x^(3/2) | (4 to 0) = 1
2/3 k (8 - 0) = 1
16/3 k = 1
k = 3/16
Hope this helped!