Find the value of g, the gravitational acceleration at Earth’s surface, in light-years per year^2?
Find the value of g, the gravitational acceleration at Earth’s surface, in light-years per year2, to three significant figures. thanks
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1 ly = 3*10^8*365*24*60^2 m = 9.4608*10^15 m
1m = 1/9.4608*10^15 ly
9.81 m = 1.0369*10^-15 ly
1 y = 365*24*60^2 s
1s = 1/3.1536*10^7 y = 3.17*10^-8 y
9.81m/s = 1.0369*10^-15/(3.17*10^-8)^2
= 1.0310 ly / y^2
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