Find the solutions of the exponential equation e^(2x)–6e^(x)+8=0?
So far this is what I have figured out but the answer is incorrect. I'm not really sure where i'm going wrong.
(e^x)^(2) - 6e^x + 8 = 0
(e^(x) - 4)(e^(x) - 2) =0
e^x = 4 and e^x= 2
Your help would be greatly appreciated.
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x = ln4, ln2
e^(2x) - 6*e^(x) + 8 = 0
(e^(x) - 4)(e^(x) - 2) = 0
e^(x) = 4 and e^(x) = 2
x = ln(4), x = ln(2).