Please?!
y ≤ 12
y ≥ 24
y ≤ 0
y ≥ 0
12x+24≥0
12x≥-24
x≥-2
Hello
If you mean √(12x + 24)...
The domain is [-2 , +Inf[, as Jack said.
That function is monotone, increasing
So it is enough to find tha value of y at the lower limit of the domain :
When x = -2, f(x) = 0 and then increasing to infinity.
Therefore the range is [0 , +inf.[ or in other words y ≥ 0
If you mean (√12x) + 24
The domain is x ≥ 0
The function is also monotone increasing
For the lower value of the domain, f(0) = 24
Then the range will be y ≥ 24
So you see all depends on the brackets...
Hope it helps
It is fair to select a best answer, whatever it is. Thank you !
Bye !
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
12x+24≥0
12x≥-24
x≥-2
Hello
If you mean √(12x + 24)...
The domain is [-2 , +Inf[, as Jack said.
That function is monotone, increasing
So it is enough to find tha value of y at the lower limit of the domain :
When x = -2, f(x) = 0 and then increasing to infinity.
Therefore the range is [0 , +inf.[ or in other words y ≥ 0
If you mean (√12x) + 24
The domain is x ≥ 0
The function is also monotone increasing
For the lower value of the domain, f(0) = 24
Then the range will be y ≥ 24
So you see all depends on the brackets...
Hope it helps
It is fair to select a best answer, whatever it is. Thank you !
Bye !