Do you recommend -3 with a multiplicity of two, and a million and seven with multiplicity a million? (x - a million)(x - 7)(x + 3)^2 Do you recommend the total element with a multiplicity of two? ((x - a million)(x - 7)(x + 3))^2 you additionally can improve the expressions, however the factorized version might desire to suffice except you have been informed to enhance them fairly.
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Verified answer
Supposing the "multiplicity 2" applies only to the -3 root:
Use the factor theorem to convert the four given roots into factors. The factor theorem tells you that if R is a root then (x - R) is a factor:
(x - 1) (x - 7) (x + 3) (x + 3)
Multiply these factors together:
x^4 - 2x^3 - 32x^2 - 30x + 63
[This question would have been better posted in the mathematics section.]
Do you recommend -3 with a multiplicity of two, and a million and seven with multiplicity a million? (x - a million)(x - 7)(x + 3)^2 Do you recommend the total element with a multiplicity of two? ((x - a million)(x - 7)(x + 3))^2 you additionally can improve the expressions, however the factorized version might desire to suffice except you have been informed to enhance them fairly.