Find the point on the line 5x+4y+2=0 which is closest to the point (0,−1)?
Find the point on the line 5x+4y+2=0 which is closest to the point (0,−1).
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Find the point on the line 5x+4y+2=0 which is closest to the point (0,−1).
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Verified answer
The line is perpendicular to the line 5x+4y+2=0 has the slope =4/5 and point (0,-1)
Therefore, ( y+1)/ x=4/5
y+1 =4/5 x
y=4/5 x -1
Find the intercept of the two line
5x+16/5 x -4 +2 =0
25x +16x -10=0
41x=10
x=10/41
y=8/41-1
=- 33/41
This point is close to point (0,-1)