Can we simplify it?
use diff of 2 squares on denominator
((√x)-8))/(x-64) assuming x not equal to 64
((√x)-8))/((√x)-8)((√x)+8))
1/((√x)+8)
okay so if x = 64 we get 1/((√64)+8) = 1/(8+8) = 1/16
So although x can't ever be 64 because the equation is undefined, the limit as x approaches 64 is 1/16.
Use (x-64) = (√x)^2 - 8^2 = ((√x)-8) ((√x)+8)
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Verified answer
Can we simplify it?
use diff of 2 squares on denominator
((√x)-8))/(x-64) assuming x not equal to 64
((√x)-8))/((√x)-8)((√x)+8))
1/((√x)+8)
okay so if x = 64 we get 1/((√64)+8) = 1/(8+8) = 1/16
So although x can't ever be 64 because the equation is undefined, the limit as x approaches 64 is 1/16.
Use (x-64) = (√x)^2 - 8^2 = ((√x)-8) ((√x)+8)