Find the limit of trigonometric function
Limit ((Theta^4 -1)/(Theta^3 -1)) as theta approaches to 1.
We can use L'Hopital's Rule.
Differentiating θ^4 = 4θ³
Differentiating θ³ = 3θ²
Hence,
lim (θ^4 - 1)/(θ³ - 1) =
x→1
lim (4θ³)/(3θ²) =
lim (4θ)/(3) =
Thus, limit = (4/3)
Using Hospital's lemma:
lim ((Î^4 -1)/(Î^3 -1)) as Î->1 is equal 4/3.
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Verified answer
We can use L'Hopital's Rule.
Differentiating θ^4 = 4θ³
Differentiating θ³ = 3θ²
Hence,
lim (θ^4 - 1)/(θ³ - 1) =
x→1
lim (4θ³)/(3θ²) =
x→1
lim (4θ)/(3) =
x→1
Thus, limit = (4/3)
Using Hospital's lemma:
lim ((Î^4 -1)/(Î^3 -1)) as Î->1 is equal 4/3.