Three balls are launched simultaneously, as in the figure. The red ball is launched at an initial velocity
Vo directed at an angle θ above the horizontal. The blue ball is launched vertically with a speed of
v1 = 15.2 m/s, and the yellow ball is launched horizontally with a speed of v2 = 3.3 m/s. The blue and red balls reach identical maximum heights and return to the ground at the same time, and the red ball returns to the ground to meet the yellow ball at the same place along the horizontal.
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Verified answer
This is a vector component problem, a bit backwards from normal.
Yellow is equiv to the x component of red, and blue the y component of red.
So magnitude of V₀ = √(V₁² + V₂²)
V₀ = √(15.2² + 3.3²) = 15.6
angle = arctan (15.2/3.3) = 77.8º