â«(1+e^x)dx = â«(1)dx + â«(e^x)dx = x + e^x + c = x + e^x + c
Separate your integral first so that you only have one term per integral. The integral of 1 is X, and the integral of e^x is e^x. Don't forget to add the constant of integration to the end since we're not evaluating it.
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Verified answer
∫(1+e^x)dx = ∫ dx + ∫ e^x dx
= x + e^x + C
â«(1+e^x)dx = â«(1)dx + â«(e^x)dx = x + e^x + c = x + e^x + c
Separate your integral first so that you only have one term per integral. The integral of 1 is X, and the integral of e^x is e^x. Don't forget to add the constant of integration to the end since we're not evaluating it.
You have to split it up into 2 separate integrals:
â«dx + â«e^x
The integral of dx is 'x' and the integral of e^x is just, 'e^x.'
Final Answer:
x+e^x + C
Integrate this expression term by term:
â« (1 + â®Ë) dx = â« 1 dx + â« â®Ë dx
â« (1 + â®Ë) dx = x + â®Ë + C
x+e^x + c
Don't forget the constant!
=x+e^x