A point on the terminal side of an angle θ is given. Find the exact value of the indicated trigonometric function of θ
(-3,-2)
Find sec θ
sec = 1/cos = 1/(-3/(sqrt(13)) = -sqrt(13) /3
r² = 9 + 4 = 13
r = √13
cos Ө = - 3 / √13
sec Ө = - √13 / 3
sec(theta) = r/x = sqrt(x^2+y^2)/x = -sqrt(13)/3,
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Verified answer
sec = 1/cos = 1/(-3/(sqrt(13)) = -sqrt(13) /3
r² = 9 + 4 = 13
r = √13
cos Ө = - 3 / √13
sec Ө = - √13 / 3
sec(theta) = r/x = sqrt(x^2+y^2)/x = -sqrt(13)/3,