whats the answer?
a. -120/169
b. 120/169
c. 60/169
d. -60/169
sin2θ = 2sinθcosθ = 2(5/13)(12/13) = 120/169
------
Ideas to save time: Use 5-12-13 Pythagorean triple.
i ll use A instead of theta
sin 2A = 2 sin A . cos A
cos A = 12 / 13
sin^2 A = 1 - cos^2 A
if u calculate value of sin A comes out to be 5/13
sin 2 A = 2 sin A cos A
= 2 X 5/13 X 12/13
= 120/ 169
ANS- B
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
sin2θ = 2sinθcosθ = 2(5/13)(12/13) = 120/169
------
Ideas to save time: Use 5-12-13 Pythagorean triple.
i ll use A instead of theta
sin 2A = 2 sin A . cos A
cos A = 12 / 13
sin^2 A = 1 - cos^2 A
if u calculate value of sin A comes out to be 5/13
sin 2 A = 2 sin A cos A
= 2 X 5/13 X 12/13
= 120/ 169
ANS- B