Find the equation of the line perpendicular to 3x – 4y = 9 and passing through (-2, -1). ?
I am beating my head against a brick wall. I know I know this one, but my brain just will not compute....
A little help?
Update:OK. So the answer I have in standard form for the original questions is x=4/3x+9
The answer I have now is x=-4/3y-10/3....... Anyone?
Thank you for the help!!!!!!! I am trying to remember algebra after 12 years of not using it. At least not thinking about it like this.
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find the slope of the first line
get the opposite reciprical of that
and thats the slope of the perpendicular line
then plug in the -2 and -1 i think
y+1=4/3(x+2)
You seem to know how to do the question, but you're just a little stuck.
Well, as the line is perpendicular to 3x - 4y = 9, you can get the gradient by using the principle of:
m1 x m2 = -1 (m is the gradient)
Then, substitute the gradient and co-ordinate values into the given equation to get the y-intercept and you're done.
you can do coordinate form
y=ROC(x--xcoordinate)+y coordinate
then you can make it into standerd form if need be
to do that u subtract the x from both sides