Find the domain of y=3√3x-3)?
Find the domain of y=3√3x-3)
a) x > 1
b) x> –1
c) x > 1
d) x > –1
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Find the domain of y=3√3x-3)
a) x > 1
b) x> –1
c) x > 1
d) x > –1
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Verified answer
I'm assuming the 3x-3 is in parentheses, and that the radical is covering it. In that case, the function exists wherever (3x-3) is greater than zero, because you can't take the square root of a negative number and get a real-number solution. So we solve the inequality
3x - 3 > 0
3x > 3
x > 1