Answer in the form e^(Ax) [ Bx^C + Dx ^E ] where C > E
Since f(x) is a product of two functions, you need to use the product rule to find the derivative of f(x) or f '(x).
f '(x) = x^6 * d/dx(e^(8x)) + d/dx(x^6) * e^(8x)
= x^6 * 8e^(8x) + 6x^5 * e^(8x).
Now you factor out e^(8x) as your GCF to get
f '(x) = e^(8x)(x^6 + 6x^5). C = 6, E = 5, so C > E.
Ben
www.mcgaheemath.com
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Since f(x) is a product of two functions, you need to use the product rule to find the derivative of f(x) or f '(x).
f '(x) = x^6 * d/dx(e^(8x)) + d/dx(x^6) * e^(8x)
= x^6 * 8e^(8x) + 6x^5 * e^(8x).
Now you factor out e^(8x) as your GCF to get
f '(x) = e^(8x)(x^6 + 6x^5). C = 6, E = 5, so C > E.
Ben
www.mcgaheemath.com