Find an equation of the tangent line to the curve at the given point. y = sin(sin x), (π, 0)?
Find an equation of the tangent line to the curve at the given point.
y = sin(sin x), (π, 0)
would it be
y=3.8-.68x
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y = sin(sin(x))
dy/dx = cos(sin(x)) * cos(x)
Slope of tangent at pt. = -1
Eqn of tangent:
y= pi-x