1. sin θ = √3/2
2. sec θ= -√2
plz show work
=> θ = sin^(-1)√3/2
i.e. θ = 60° or 120°
-----------------------------------------
=> cos θ = -1/√2
=> θ = cos^(-1)(-1/√2)
i.e. θ = ±135°
=> θ = 135° or 225°
:)>
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Verified answer
1. sin θ = √3/2
=> θ = sin^(-1)√3/2
i.e. θ = 60° or 120°
-----------------------------------------
2. sec θ= -√2
=> cos θ = -1/√2
=> θ = cos^(-1)(-1/√2)
i.e. θ = ±135°
=> θ = 135° or 225°
:)>