with the aid of utilising actuality he's only sixteen As you have, and a good variety of persons do ask why Diana can, it is with the aid of utilising quantity of hours a sixteen year old can artwork in an afternoon, yet Diana is 17, as without postpone as you turn 17 the regulations substitute, and so Diana is authorized on Xtra ingredient and Eoghan isn't.
Answers & Comments
Verified answer
Difference of two squares:
(a + b)(a - b) = a^2 - ab + ab - b^2 = a^2 - b^2
The form a^2 - b^2 factors to (a + b)(a - b)
Here a = 6x, b = 2y
36x^2 - 4y^2 = (6x + 2y)(6x - 2y)
You probably should factor out a 4 first
36x^2 - 4y2 = 4(9x^2 - y^2) = 4(3x + y)(3x - y)
36x^2 - 4y^2 (factor out greatest common factor, which is 4)
4(9x^2 - y^2) (factor by difference of two squares: a^2 - b^2 = (a + b)(a - b))
4(3x + 1)(3x - 1) <===ANSWER
with the aid of utilising actuality he's only sixteen As you have, and a good variety of persons do ask why Diana can, it is with the aid of utilising quantity of hours a sixteen year old can artwork in an afternoon, yet Diana is 17, as without postpone as you turn 17 the regulations substitute, and so Diana is authorized on Xtra ingredient and Eoghan isn't.
36x^2 - 4y^2
4(9x^2 - y^2)
4((3x)^2 - y^2)
4(3x + y)(3x - y)
(6x+2y)(6x-2y)
no stages, rule of squares.
Moonroses approach works is fully factored, except final answer would be 4(3x+y)(3x-y)
36x^2 - 4y^2 = 36x^2 - 12xy + 12xy - 4y^2
= 12x (3x - y) + 4y(3x - 4y)
= (12x + 4y)(3x-y)
= 2(6x+2y)(3x-y)
= (6x+2y)(6x-2y)
4x^2(9 - 1)
basically find the common factor between the two polynomials, in this case, it would be 4x^2
There are multiple ways to factor this, another way would be
(6x + 2y)(6x - 2y)
36x^2 – 4y^2
(6x-2y)(6x+2y)
4(9x^2 - y^2)
= 4(3x - y)(3x + y)