4(√-12) + 3(√-27) = 4(√4√-3) + 3(√9√-3)
= 8i√3 + 9i√3
= 17i√3
––––––––––––––
4sqrt(- 12) + 3sqrt(- 27) =
4sqrt(4)sqrt(3)sqrt(- 1) + 3sqrt(9)sqrt(3)sqrt(- 1) =
4(2)sqrt(3)i + 3(3)sqrt(3)i =
8dqrt(3)i + 9sqrt(3)i =
11sqrt(3)i
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Verified answer
4(√-12) + 3(√-27) = 4(√4√-3) + 3(√9√-3)
= 8i√3 + 9i√3
= 17i√3
––––––––––––––
4sqrt(- 12) + 3sqrt(- 27) =
4sqrt(4)sqrt(3)sqrt(- 1) + 3sqrt(9)sqrt(3)sqrt(- 1) =
4(2)sqrt(3)i + 3(3)sqrt(3)i =
8dqrt(3)i + 9sqrt(3)i =
11sqrt(3)i