lim x→π/ 6 (cosx−cos^2 x)/ x
By direct substitution, we obtain (cos(π/6) - cos^2(π/6)) / (π/6)
= (√3/2 - (√3/2)^2) * (6/π)
= (√3/2 - 3/4) * (6/π)
= (3/(2π)) (2√3 - 3).
I hope this helps!
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Verified answer
By direct substitution, we obtain (cos(π/6) - cos^2(π/6)) / (π/6)
= (√3/2 - (√3/2)^2) * (6/π)
= (√3/2 - 3/4) * (6/π)
= (3/(2π)) (2√3 - 3).
I hope this helps!