Evaluate the definite integral of ∫1,4 (√u)du?
Please show your work so I know how to do others like this later on. Thanks!
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Please show your work so I know how to do others like this later on. Thanks!
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∫[1,4] √u du= ∫[1,4] u^½ du= u^(½+1)/(½+1) |[1,4]= 2u^(3/2)/3 |[1,4]= 2*4^(3/2)/3 -2*1^(3/2)/3=14/3
http://www.wolframalpha.com/input/?i=+%E2%88%AB%5B...
u^1/2
2/3u^3/2
2/3(4)^3/2 - 2/3(1)^3/2