Evaluate
4(4+√x)^2
∫ 2√x dx
1
ugh.
This is why I was an English major.
11
=(4/3) [4(4+Tx)^3-2]
.....dx...............A..........B ?---------------- =.-------- + -------- ..(x-2)(x+a million)......x-2........x+a million a million = A(x+a million) + B(x-2) whilst x=-a million a million=A(-a million+a million) + B(-a million-2) a million=-3B B=-a million/3 whilst x= 2 a million=A(2+a million) + B(2-2) a million=3A A=a million/3 ....a million/3......a million/3 =[--------- - ----------]dx ....x-2.......x+a million ...........dx...............dx =a million/3 ?---------- - a million/3?---------- ..........x-2..............x+a million =a million/3ln(x-2) - a million/3ln(x+a million) +C =a million/3[ln(x-2) - ln(x+a million)] +C answer//
6'2" or 9". Which do you like?
furby
No. I won't.
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Verified answer
ugh.
This is why I was an English major.
11
=(4/3) [4(4+Tx)^3-2]
.....dx...............A..........B ?---------------- =.-------- + -------- ..(x-2)(x+a million)......x-2........x+a million a million = A(x+a million) + B(x-2) whilst x=-a million a million=A(-a million+a million) + B(-a million-2) a million=-3B B=-a million/3 whilst x= 2 a million=A(2+a million) + B(2-2) a million=3A A=a million/3 ....a million/3......a million/3 =[--------- - ----------]dx ....x-2.......x+a million ...........dx...............dx =a million/3 ?---------- - a million/3?---------- ..........x-2..............x+a million =a million/3ln(x-2) - a million/3ln(x+a million) +C =a million/3[ln(x-2) - ln(x+a million)] +C answer//
6'2" or 9". Which do you like?
furby
No. I won't.