Yep!
The reference angle for 13π/4 is π/4. Then...
arccos(sin(π/4)) = arccos(√(2)/2) = π/4!
I hope this helps!
cos - 1(sin (13pi/4))
cos - 1 (sin (pi/4))
cos - 1 sqrt(2)/2
pi/4
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Verified answer
Yep!
The reference angle for 13π/4 is π/4. Then...
arccos(sin(π/4)) = arccos(√(2)/2) = π/4!
I hope this helps!
cos - 1(sin (13pi/4))
cos - 1 (sin (pi/4))
cos - 1 sqrt(2)/2
pi/4