Verified answer

continue with Dan's solution ....

substitute 4 in the place of x

√(2x+8)+6

=√(2*4+8) + 6

=√16 + 6

= 4 + 6 [Note: √16 = 4 ]

= 10

= RHS

√(2x+8) + 6 = 10

√(2x+8) = 10 - 6

√(2x+8) = 4

2x+8 = 4^2

2x+8 = 16

2x= 16-8

2x=8

x=4

hope it is easily understood... : )

x=4. the sq root of 2 times 4(x) plus 8 is 4, 4 plus 6 equals 10.

√(2x+8) + 6 = 10

√(2x+8)=10-6

√(2x+8)=4

2x+8= 4^2

2x+8= 16

2x= 16-8

2x= 8

x= 8/2

x= 4

Subtract six from both sides

(2x+8)^1/2 = 4

Square both sides

2x+8=16

2x=8

x=4

is the entire quantity under the squareroot?