If you divide the ignodicious summary of the subtractive numeral from the larger value of the summed up product, you will end up with the larger numerical value of the forthright problematic subtraction situation.
After that, take the parenthesis and reverse them to the side A with the dividical numerical worth.
Answers & Comments
Verified answer
√-24/√-2 . . .first factor the primes:
√(-1)(2*2*2*3) AND √(-1)(2) . . .We have:
[2√(-1)(2)(3)]/√(1-)(2)
- - -
Answer: 2√3
â12 or 2â3
â12 or 2â3
â+12
= â4*â3
=2â3
â-24/â-2 = â(-24/-2) = â(24/2) = â12 = â(4*3) = 2â3
I opted not to introduce the imaginary number notation "i" among these steps.
Simple!
If you divide the ignodicious summary of the subtractive numeral from the larger value of the summed up product, you will end up with the larger numerical value of the forthright problematic subtraction situation.
After that, take the parenthesis and reverse them to the side A with the dividical numerical worth.
Easy as pie.
V-24/V-2
=V24*i/V2*i [i=v(-1)]
=V12
=V4.3
=2V3 ANS
correct answer is square root of 12
sqrt(-24) = sqrt(-1 * 4 * 2 * 3) = sqrt(-1) * sqrt(4) * sqrt(2) * sqrt(3) = 2 * i * sqrt(2) * sqrt(3)
sqrt(-2) = sqrt(-1 * 2) = sqrt(-1) sqrt(2) = i * sqrt(2)
So sqrt(-24) / sqrt(-2) = (2 * i * sqrt(2) * sqrt(3)) / (i * sqrt(2)) = 2 sqrt(3).
sqrt(12) you get the imaganary "i" in both the top and bottom so they cancel out