...so slowly that the enthalpy change of the process mst be obtained indirectly. Determine ∆H rxn for:
C(diamond) ---> C(graphite)
with equations from the following list:
(1) C(diamond) + O2(g) --> CO2(g) ∆H= -395.4 kJ
(2) 2CO2(g) ---> 2CO(g) + O2(g) ∆H= 566.0 kJ
(3) C(graphite) + O2(g) ---> CO2(g) ∆H= -393.5 kJ
(4) 2CO(g) ---> C(graphite) + CO2(g) ∆H= -172.5 kJ
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Verified answer
Asia,
The only two equations you need out of this list are (1) and (3):
(1) C(diamond) + O2(g) --> CO2(g) ∆H= -395.4 kJ
(3) C(graphite) + O2(g) ---> CO2(g) ∆H= -393.5 kJ
If we reverse equation (3), we get
(3') CO2(g) --> C(graphite) + O2(g) ∆H= +393.5 kJ
Add equation 1 to equation 3', cancel out the common terms for CO2 and O2, and you get
(1) C(diamond) + O2(g) --> CO2(g) ∆H= -395.4 kJ
(3') CO2(g) --> C(graphite) + O2(g) ∆H= +393.5 kJ
C(diamond) ---> C(graphite) ∆H= -1.9 kJ
or conversely,
C(graphite) ---> C(diamond) ∆H= 1.9 kJ
Doesn't seem like ***that*** much to make diamonds; maybe we can go into business??? Hope that helped!