design a sequential circuit that finds C=AxB,where A and B are 4‐bit numbers,and C is 8‐bit number.?

Use one 74194 for A, one 74194 IC for B, and two 74194 ICs for C

note:I designed a binary multiplier. This is a combinational circuit that finds C=AxB, where A and B are 2‐bit numbers and C is a 4‐bits number.

Use your design in a sequential circuitthatfinds C=AxB, where A and B are 2‐bit numbers, and C is 4‐bit number.Use one 74194 IC for each register.

S0 – Idle State. Move to S1 if START=1

S1 – Load A,B. Move to S1

S2 – Load C with result. Move to S2

2. Use the multiplier you designed in a sequential circuit that finds C=AxB, where A and B are 4‐bit

numbers, and C is 8‐bit number.

Use one 74194 for A, one 74194 IC for B, and two 74194 ICs for C.

A = A2A1

B= B2B1

A= a3a2 a1a0

A2=a3a2, A1=a1a0

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