calculate delta H for the reaction:
C3H8 +5 O2 --> 3CO2 + 4H2O
For the reaction, C3H8 +5 O2 --> 3CO2 + 4H2O , delta H° = -2046 KJ and the heat of vaporization of water is 44.0 kj/mol
a) -2222 kj
b) -2002 kj
c) -1870 kj
d) -2090 kj
please help, and please explain how to calculate this
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Verified answer
-2046 + 44 = -2002 kJ/mol
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