De Broglie postulated that the relationship λ= h/p is valid for relativistic particles.?
De Broglie postulated that the relationship λ= h/p is valid for relativistic particles. What is the de Broglie wavelength for a (relativistic) electron having a kinetic energy of 3.00 MeV?
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Or you can recognize that when P = Mv where M = m/sqrt(1 - (v/c)^2) then K = Mvc = Pc = 3 MeV so that P = 3 MeV/c
So we have L = h/P --> L = hc/3 = 1240/3 = 413 nm. ANS.
You know E^2 = E0^2 + (pc)^2 where E = total energy = mc^2 + kinetic energy, and E0 = rest energy = mc^2.
So you can plug in values for E and E0 and solve for p, then plug that into the de Broglie relationship to find lambda. mc^2 for an electron is 511 keV = 0.511 MeV.