¿así, sin saludito, en seco?
Como no, sus deseos son órdenes...
2 ln(x^2 + 1) + C
5 atan(x) + C
integral de 4x/(x^2+1)
integral de du/u= ln(u) +C
Let be U= X^2 +1 ,so du= 2x
integ(2x/(x^2+1))= integ(u/du)= ln(u)= ln(x^2+1) +C
Integral de 4x/(x^2+1)=
2*integ(2x/(x^2+1)=
***** 2*ln(x^2+1)+C
******************************************
Iintegral de 5/(x^2+1)
x=tgu=(senu/cosu)
d/du tgu= 1+ (tgu)^2
d/du(tan)^(-1)(u) =(1/(tgu)^2+1)
integ[ d/du( tgu)^(-1)
= integral(1/(tgu)^2+1)=integral(1/(x^2+1)
(tgu)^-1= integral (1/(tgu)^2+1)
integral 5/(x^2+1)=
5 integral(1/x^2+1)= 5(tgu)^(-1) +C
= 5tan^(-1)(x) +C
=*****5 arctg(x)+C
.
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¿así, sin saludito, en seco?
Como no, sus deseos son órdenes...
2 ln(x^2 + 1) + C
5 atan(x) + C
integral de 4x/(x^2+1)
integral de du/u= ln(u) +C
Let be U= X^2 +1 ,so du= 2x
integ(2x/(x^2+1))= integ(u/du)= ln(u)= ln(x^2+1) +C
Integral de 4x/(x^2+1)=
2*integ(2x/(x^2+1)=
***** 2*ln(x^2+1)+C
******************************************
Iintegral de 5/(x^2+1)
x=tgu=(senu/cosu)
d/du tgu= 1+ (tgu)^2
d/du(tan)^(-1)(u) =(1/(tgu)^2+1)
integ[ d/du( tgu)^(-1)
= integral(1/(tgu)^2+1)=integral(1/(x^2+1)
(tgu)^-1= integral (1/(tgu)^2+1)
integral 5/(x^2+1)=
5 integral(1/x^2+1)= 5(tgu)^(-1) +C
= 5tan^(-1)(x) +C
=*****5 arctg(x)+C
.