Cr(OH)subs3 + BrO [ - charge] → CrOsubs4 [ 2- charge] + Br [ - charge]?
Redox Equations
Ion-electron method
Complete and balance.
--
Subs = subscript
Cr(OH)3 and CrO4
BrO has a negative ( - ) charge
CrO4 has a 2- charge
Br has a - charge
More Questions From This User See All
Answers & Comments
Verified answer
Cr(OH)3 + H2O >> CrO42- + 5H+ + 3e-)x2
BrO- + 2H+ + 2e->> Br- + H2O)x3
2 Cr(OH)3 + 3 BrO- >> 2 CrO42- + 3 Br-+ H2O + 4H+
Because the reaction occurs in basic solution we add 4 OH- on the left and on the right side ( 4 H+ + 4 OH- >> 4 H2O)
2 Cr(OH)3 + 3 BrO- + 4 OH- >> 2 CrO42- + 3 Br- + 5 H2O