Verified answer

[(2pm^-1q^0)^-4 • 2m^-1p^3] / (2pq^2)

= [(2pm^-1)^-4 • 2m^-1p^3] / (2pq^2) -- since q^0 = 1

= (2^-4 p^-4 m^4) (2 m^-1 p^3) / (2pq^2) -- because (x^j)^k = x^(jk)

= 2^(-4+1) m^(4-1) p^(-4+3) / (2pq^2) -- because (x^j) (x^k) = x^(j+k)

= 2^-3 m^3 p^-1 (2^-1 p^-1 q^-2) -- because 1/(x^n) = x^-n

= 2^-4 m^3 p^-2 q^-2

= m^3 / (2^4 p^2 q^2)

= m^3 / (16 p^2 q^2)