f(x) = 3x - 2 and g(x) = x^2 - 1
(f+g)(x) = 3x - 2 + x^2 - 1 = x^2 + 3x - 3
(f+g)(-4) = (-4)^2 + 3(-4) - 3
= 16 - 12 - 3
= 1
that's it! ;)
Ok... So...
(f + g)(-4) = (3x-2 + x^2-1)(-4)
= (x^2 + 3x -3)(-4)
= -4x^2 - 12x + 12
= (2x- )(-2x- ).... U factorise basically i guess :D
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Verified answer
f(x) = 3x - 2 and g(x) = x^2 - 1
(f+g)(x) = 3x - 2 + x^2 - 1 = x^2 + 3x - 3
(f+g)(-4) = (-4)^2 + 3(-4) - 3
= 16 - 12 - 3
= 1
that's it! ;)
Ok... So...
(f + g)(-4) = (3x-2 + x^2-1)(-4)
= (x^2 + 3x -3)(-4)
= -4x^2 - 12x + 12
= (2x- )(-2x- ).... U factorise basically i guess :D