The average value of some function y = f(x) on the interval [a,b] is defined as:
1/(b - a)*∫f(x) dx from a to b
In this case:
Average value = 4/π * ∫cos(2x) dx from 0 to π/4 = 4/π *[1/2*sin(2x) eval. from 0 to π/4]
= 4/π*[1/2] = 2/π
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
The average value of some function y = f(x) on the interval [a,b] is defined as:
1/(b - a)*∫f(x) dx from a to b
In this case:
Average value = 4/π * ∫cos(2x) dx from 0 to π/4 = 4/π *[1/2*sin(2x) eval. from 0 to π/4]
= 4/π*[1/2] = 2/π