Ajudaria muiito se vcs postasem como resolve
Agradeço des de ja :D
x²+12x=0
x(x+12)=0
x=0
x+12=0
x=-12
S(0,-12)
x.(x +12)=0
x=0 ou x=-12
x(x + 12) = 0
x = 0
ou
x + 12 = 0
x = -12
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Verified answer
x²+12x=0
x(x+12)=0
x=0
x+12=0
x=-12
S(0,-12)
x.(x +12)=0
x=0 ou x=-12
x(x + 12) = 0
x = 0
ou
x + 12 = 0
x = -12