f(x)=x²-22x-240
x²-22x-240=0
∆=(-22)²-4(1)(-240)=
484+960=1444
√1444=38
x=(22±38)/2
x'=-16/2=-8
x"=60/2=30
S={-8,30)
resolva por Báskara
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Verified answer
x²-22x-240=0
∆=(-22)²-4(1)(-240)=
484+960=1444
√1444=38
x=(22±38)/2
x'=-16/2=-8
x"=60/2=30
S={-8,30)
resolva por Báskara