q = mC∆T
q = heat = ?
m = mass = 39.0 g
C = specific heat = 4.184 J/g/deg for water
∆T = change in temperature = 89.0 - 22.5 = 66.6 degrees C
q = (39.0 g)(4.184 J/g/deg)(66.5.deg) = 10,851 J
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q = mC∆T
q = heat = ?
m = mass = 39.0 g
C = specific heat = 4.184 J/g/deg for water
∆T = change in temperature = 89.0 - 22.5 = 66.6 degrees C
q = (39.0 g)(4.184 J/g/deg)(66.5.deg) = 10,851 J