Clausius Clapeyron equation:
ln(P1/P1) = ∆Hvap/R (1/T2 - 1/T1)
P1 = 425 torr
T1 = 25 + 273 = 298K
P2 = 760 torr
T2 = 50.2+273 = 323.2
R = 8.314
∆Hvap = ?
ln(425/760) = ∆H/R (1/323.2 - 1/298)
-0.581 = ∆H/8.314 (0.003096 - 0.00356)
-0.581 =∆H/8.314 (-0.000464)
-4.830/-0.000464 = ∆H
∆Hvap = 10,410 J = 10.4 kJ
LIFE IS MEANINGLESS **** BITCHES IN THE BEEN
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Clausius Clapeyron equation:
ln(P1/P1) = ∆Hvap/R (1/T2 - 1/T1)
P1 = 425 torr
T1 = 25 + 273 = 298K
P2 = 760 torr
T2 = 50.2+273 = 323.2
R = 8.314
∆Hvap = ?
ln(425/760) = ∆H/R (1/323.2 - 1/298)
-0.581 = ∆H/8.314 (0.003096 - 0.00356)
-0.581 =∆H/8.314 (-0.000464)
-4.830/-0.000464 = ∆H
∆Hvap = 10,410 J = 10.4 kJ
LIFE IS MEANINGLESS **** BITCHES IN THE BEEN