Can you Please help me Solve. 3x^2 – 75 = 0?
A.) x = 5 and x = –5
B.) x = 25
C.) x = 3 and x = 25
D.) x = 5
Solve. 2x^2 + 12x= 10
A.) –3 ± √14
B.) –3 ± 2√2
C.) –3 ± √19
D.) –3 ± √29
Solve. 6x^2 = 12x – 20
A.) 3+- i sqrt 21/3
B.) 3+- i sqrt 39/3
C.) 1 ± 2i√21
D.) 1 – i√39
Please help. Will give best answerr <3
More Questions From This User See All
Answers & Comments
Verified answer
1. 3x^2 – 75 = 0
x^2 =75/3 =25
x = + 5 or -5
Hence, A)
2. 2x^2 + 12x= 10
2x^2+12x-10 =0
2(x^2+6x-5)=0
2[(x+3)^2-9]-5
2[(x+3)^2-14]
2(x+3)^2-28
2(x+3)^2 =28
(x+3)^2 =14
(x+3) = +/- sqr.rt 14
x = +/- [sqr.rt 14] -3
Hence, A)
3. 6x^2 = 12x – 20
6x^2-12x+20 =0
6(x^2-2x+(20/6))=0
6[(x-1)^2-1]+20/6
6[(x-1)^2+14
6(x-1)^2 = -14
-3/7(x-1)^2 =1
Hence, A)