can you help me simplify (6^√2x^3y^4)^30? I'm stuck on it?
I'm studying for my finals. I need help solving it and explaining the steps, because if I just get an answer that would not help me solve similar equations like this.
Update:did you read it right or am i really that lost. It's open parenthesis, sixth root of the square root 2x to the third power, y to the fourth power close parenthesis thirty power. (ⁿ√2xⁿyⁿ)ⁿ
the first n is 6, second n is 3, third n is 4 and the fourth n is 30
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Then it would simply be 2^{30/6) x^{3*30} y^{4*30}= 2^5 x^{90} y^{120}
Okay so you have something to the power of a radical... then raised to another power... Lets get this started :\
First things first is to simplify everything you can...
6^(â(2x^3y^4))^30 If you wanted to you could pull out a xy^2 from the radical
After you pull out the xy^2 multiply everything by 30 because when you raise a power to a power you just multiply the powers...
6^(30xy^2â(2x))
and that's your answer... unless you're solving for a certain variable... you could take a log and bring down you power...
(30xy^2â(2x))*ln6