It really depends where the brackets are if there are any. If there are none then
sqrt(8)*x - 4
sqrt((2*2*2))x - 4
2*sqrt(2)x - 4
2[*sqrt(2)x - 2)
If the brackets are like this
sqrt(8x - 4) then you get
sqrt(4(2x - 1)) which reduces to
2*sqrt(2x - 1)
There are other cases, but I think you get the idea
4 square root of 2x-1
√(8x-4) = √4(2x-1) = √2²(2x-1) = 2√(2x-1)
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Verified answer
It really depends where the brackets are if there are any. If there are none then
sqrt(8)*x - 4
sqrt((2*2*2))x - 4
2*sqrt(2)x - 4
2[*sqrt(2)x - 2)
If the brackets are like this
sqrt(8x - 4) then you get
sqrt(4(2x - 1)) which reduces to
2*sqrt(2x - 1)
There are other cases, but I think you get the idea
4 square root of 2x-1
√(8x-4) = √4(2x-1) = √2²(2x-1) = 2√(2x-1)