(At 35°C, P
o
water
= 42.2 mmHg.)
37.3/42.2 = 0.884 = mole fraction of H2O in the solution
mole fraction of urea = 1.000 - 0.884 = 0.116
moles H2O = 197 g x 1 mol/18 g = 10.94 moles H2O
moles urea = x
x/10.94 + x = 0.116
x = 1.44 moles urea
mass urea = 1.44 moles x 60 g/mole = 86.4 g of urea
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Verified answer
37.3/42.2 = 0.884 = mole fraction of H2O in the solution
mole fraction of urea = 1.000 - 0.884 = 0.116
moles H2O = 197 g x 1 mol/18 g = 10.94 moles H2O
moles urea = x
x/10.94 + x = 0.116
x = 1.44 moles urea
mass urea = 1.44 moles x 60 g/mole = 86.4 g of urea