Calculate the margin of error= z α/12 * α/ sqrt n if the necessary requirements are satisfied. The confidence?
Calculate the margin of error= z α/12 * α/ sqrt (n) if the necessary requirements are satisfied.
The confidence level is 99%, the sample sizes is n=124, and σ= 12. Are the necessary requirements satisfied?
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Joe
The Margin of Error = (z*)(s) / sqrt n
where z* = 2.576 from Standard Normal table using 1%/2 = 0.005 area in each tail.
ME = = (2.576)(12) / sqrt 124 = 2.78
hope that helped