Calculate the amount of heat required to convert 55 g of ice at −12◦ C completely to steam at 123 ◦C?
Consider the following specific heats
SHH2O(s) = 2.09 J/g ·◦C,
SHH2O(ℓ) = 4.18 J/g ·◦C, and
SHH2O(g) = 2.03 J/g ·◦C.
The heat of fusion for water is 334 J/g and
the heat of vaporization for water is 2260 J/g.
Calculate the amount of heat required to
convert 55 g of ice at −12◦ C completely to steam at 123 ◦C.
Answer in units of kJ
Please help!! I can't find this in my notes. :(
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Verified answer
warming the ice to °C:
(55 g) x (2.09 J/g ·°C) x (12 °C) = 1379.4 J
melting the ice at °C:
(55 g) x (334 J/g) = 18370 J
warming the water from 0°C to 100°C:
(55 g) x (4.18 J/g ·°C) x (100 °C) = 22990 J
vaporizing the water at 100 °C:
(55 g) x (2260 J/g) = 124300 J
heating the steam from 100 °C to 123 °C:
(55 g) x (2.03 J/g ·°C) x (23 °C) = 2567.95 J
Summing up all five heats:
170 kJ