Benzene has a heat of vaporization of 30.72 kJ/mol and a normal boiling point of 80.1°C?
Benzene has a heat of vaporization of 30.72 kJ/mol and a normal boiling point of 80.1°C. At what temperature does benzene boil when the external pressure is 517 torr?
I got 69.36 deg C but its wrong
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use the clausius clapeyron equation
ln(P1/P2) = (dHvap/R) x (1/T2 - 1/T1)
where..
P1 = 1atm = 760torr
P2 = 517torr
dHvap = 30720 J/mole
R = 8.314 J/moleK
T1 = 80.1+273.15 = 350.25K
T2 = ?????
rearrange for T2 and solve...