Verified answer

Redox equation....

Redox equations must be both mass balanced and charge balanced.

Sn^4+ + H2(g) --> Sn(s) + 2H+ ............. not charge balanced

Sn^4+ + 4e- --> Sn ................... reduction half-reaction

2(H2 --> 2H^+ + 2e-) ................ oxidation half-reaction

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Sn^4+ + 2H2(g) --> Sn(s) + 4H+ ............. balanced net ionic equation

Sn^4+ + 2H2 = Sn + 4H^+

Sn+4 + 2H2 ----> Sn + 4H+