Dado que d=vt,, se midieron t =24.36 ± 0.05 seg y v=13.71 ± 0.03 m/s, exprese adecuadamente la distancia y la incerteza de ésta
Hola
si tomamos logaritmos
ln(d) = ln(v) + ln(t)
diferenciamos
d(d) / d = d(v)/ v + d(t) / t
Eso significa que los errores relativos se suman
d(v)/v = 0.05/24.36 = 0.00205
d(t)/t = 0.03/13.71 = 0.00219
Sumamos
d (d)/d = 0.00424
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Valor principal
d = 24.36 * 13.71 = 333.98 m
incerteza
d (d) = 333.98 * 0.00424
d (d) = 1.41 m
d = 333.98 ± 1.41 m
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Answers & Comments
Hola
si tomamos logaritmos
ln(d) = ln(v) + ln(t)
diferenciamos
d(d) / d = d(v)/ v + d(t) / t
Eso significa que los errores relativos se suman
d(v)/v = 0.05/24.36 = 0.00205
d(t)/t = 0.03/13.71 = 0.00219
Sumamos
d (d)/d = 0.00424
********************
Valor principal
d = 24.36 * 13.71 = 333.98 m
incerteza
d (d) = 333.98 * 0.00424
d (d) = 1.41 m
d = 333.98 ± 1.41 m
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