An ice cube of volume 16.1 cm3 is initially at a temperature of -22.6°C.How much heat is required to convert..?
..into steam. Please help. I'm so confused! Thank you!
I know that:
specific heat of water is 4.186 kJ/kgC
specific heat of ice is 2.06 kJ/kgC
specific heat of steam is 2.1 kJ/kgK
heat of fusion of ice is 334 kJ/kg
heat of vaporization of water is 2256 kJ/kg
density of water at 20C = 0.998 g/cm³ = 998 kg/m³
density of ice at 0C = 0.917 g/cm³ = 917 kg/m³
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Verified answer
treat it as a bunch of steps.
first use the density to convert amount of ice to kg.
hint, use dimensional analysis.
1. heat required to warm the ice to 0º from –22.6º(hint, use 2.06 kJ/kgC)
2. heat required to melt ice (use 334 kJ/kg)
3. heat to warm the water from 0º to 100º
4. heat to boil the water
now add the 4 up to get total energy required.
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